Explanation: वजाबाकी / बेरीज छेद समान असतांना
1) \[\frac{x-5}{2x+3}=\frac{3x+11}{2x+3}=?\] (यात छेद समान आहे)
Explanation:\[\frac{x-5+3x+11}{2x+3}=\frac{4x+6}{2x+3}=\frac{2\left ( 2x+3 \right )}{2x+3}=2\]
2) \[\frac{4x}{x-1}-\frac{x+1}{x-1}=?\]
Explanation: \[\frac{4x-\left ( x+1 \right )}{x-1}-\frac{4x-x-1}{x-1}=\frac{3x-1}{x-1}\]
3) \[\frac{x^{3}}{x^{2}2^{xy}+y^{2}}+\frac{8y^{3}}{x^{2}-2^{xy}+y^{2}}=?\]
Explanation: \[\frac{x^{3}}{x^{2}2^{xy}+y^{2}}+\frac{8y^{3}}{x^{2}-2^{xy}+y^{2}}\\ (a^{3}+b^{3}) = (a+b)(a^{2}-ab+b^{2})\\ \frac{x^{3}+\left ( 2y \right )^{2}}{x^{2}-2^{xy}+y^{2}} = \frac{\left ( x+2y \right )\left ( x^{2}-2xy+y^{2} \right )}{x^{2}-2^{xy}+y^{2}}=x+2y\]
4) \[\frac{5x+8}{x^{2}-9}-\frac{3x-2}{x^{2}-9}=?\]
Explanation:\[\frac{5x+8-\left ( 3x+2 \right )}{x^{2}-3^{2}}=\frac{5x+8-3x-2}{\left ( x+3 \right )\left ( x-3 \right )}\\ =\frac{2x+6}{\left ( x+3 \right )\left ( x-3 \right )}\\ =\frac{2x+3}{\left ( x+3 \right )\left ( x-3 \right )}\\ =\frac{2}{x-3}\]
5) 5x+4y+2z व 3x-5y-4z यांची बेरीज किती?
Explanation: 5x+4y+2z+3x-5y-4z
5x+3x+4y-5y+2z-4z
8x-y-2z